tag:blogger.com,1999:blog-5439168179960787195.post832784436293737285..comments2019-08-23T17:34:21.909+10:00Comments on Condensed concepts: Desperately seeking spin liquids IIIRoss H. McKenziehttp://www.blogger.com/profile/09950455939572097456noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-5439168179960787195.post-58637114506130972892010-02-07T07:45:01.020+10:002010-02-07T07:45:01.020+10:00Hi Ross,
Bruce's review is very nice indeed. ...Hi Ross,<br /><br />Bruce's review is very nice indeed. Too bad it's published in an obscure journal and is not available on the arXiv. Among other things, Bruce shows an artist's rendition of spinons in a Heisenberg antiferromagnet on kagome. <br /><br />Here is my take on those spinons: <a href="http://arxiv.org/abs/0902.0378" rel="nofollow">arXiv:0902.0378</a>oleghttps://www.blogger.com/profile/11644793385433232819noreply@blogger.comtag:blogger.com,1999:blog-5439168179960787195.post-8786474420716444412010-02-05T13:18:09.176+10:002010-02-05T13:18:09.176+10:00At the end of Bruce's talk, I felt that I unde...At the end of Bruce's talk, I felt that I understood the spin-liquid concept more than I ever had before. <br /><br />Much of this had to do with his last statements, which seemed to suggest that a defining characteristic of such a state was simultaneous permutation symmetry in one-body and many-body spaces. In other words, that the state transforms as the totally symmetric representation of the symmetric (permutation) group in both the one-body and many-body spaces.<br /><br />For some reason, it was easier for me to see it in terms of permutation symmetry, rather than the usual statements about ordering and translational invariance. This is probably because, being trained in quantum chemistry, I am used to thinking about the symmetric group, but not used to thinking about translational invariance (molecules don't have this).<br /><br />After some thought and hand-waving in front of a mirror, I've convinced myself that this is probably a necessary consequence of the translational symmetry in an infinite system. If choosing a covering means choosing an origin, then all coverings must be equally weighted in the state. <br /><br />I have a wierd feeling that this has something to do with a paper that I found and haven't yet read, about how the symmetric group and the general linear group are dual to one another. Maybe I should bump that up the list.Seth Olsenhttps://www.blogger.com/profile/09304457461800104790noreply@blogger.com